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Graph a parabola by finding the vertex and using the line of symmetry and the yinterceptFind the equation of common tangent to the parabola y 2 = 4x and x 2 = 32y Advertisement Remove all ads Solution Show Solution Given equation of the parabola is y 2 = 4x Comparing this equation with y 2 = 4ax, we get 4a = 4 ∴ a = 1 Let the equation of common tangent beDetermine if x 2 4x8y12=0 is the equation of a parabola If so, find the coordinates of the vertex and the focus and the equation of the directrix Since only the x terms are quadratic, we only need complete the square on these terms Solution Graph The Parabola Y X2 4x 6 Parabola y=4x-x^2

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